国外的物理题Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the init

国外的物理题Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the init
国外的物理题
Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the initial speed of the bullet be vo = 136 m/s and the angle between the vector ~v0 and the x-axis be θ = 53.4◦and AB = 97.6 m. The distance OB is the x-coordinate of the target. The acceleration of gravity is 9.8 m/s2 .Determine the height of BP. Answer in units of m.
抱歉各位 没有崇洋媚外的意思 只是怕我翻译的不好 让大家误解了原题目的意思。。。
那我就试着翻译下：
某人在O点处朝A点处的目标开枪，开枪的同时目标从A点处垂直往下掉。子弹在P点处击中目标（P点是垂直线AB某一点位置） 子弹的初速度是136米每秒而且与X轴的角度是53.4度 AB=97。6米 OB是枪与目标的水平距离。。 重力加速度=9.8m/s^2 求BP的高度。

国外的物理题Consider the setup of a gun aimed at a target located at the point A. At t = 0 the gun is fired at the same time the target is dropped from A. The bullet hits the target at a point P which is along the vertical line AB. Let the init
Vx=136*COS 53.4°=81.08M/S
Vy=136*SIN 53.4°=109.2M/S
BP=（109.2-gt+109.2）t/2
AP=1/2gt^2
AP+BP=AB=97.6M
（109.2-gt+109.2）t/2 + 1/2gt^2=97.6
g=9.8
109.2t=97.6
t=97.6/109.2
BP=109.2t-1/2gt^2=97.6-3.9=93.7M

翻译成中文我再来回答

本质就一个平抛物体运动，
可以看成是：水平方向做匀速直线运动，竖直方向做自由落体运动。
其他的依照实际情况讨论。也就具体问题，具体分析了。
我会英语，但在中国我只使用汉语。

分析：子弹受重力作用，忽略阻力，作向上斜抛运动，其方向可以分解为水平和竖直两个方向。目标作自由落体运动。根据题目意思有：
Sob=Sab/tan53.4 1
v*cos53.4*t=Sob 2
Sap=1/2gt^2 3
有 Sap=1/2g(Sab/sin53....

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分析：子弹受重力作用，忽略阻力，作向上斜抛运动，其方向可以分解为水平和竖直两个方向。目标作自由落体运动。根据题目意思有：
Sob=Sab/tan53.4 1
v*cos53.4*t=Sob 2
Sap=1/2gt^2 3
有 Sap=1/2g(Sab/sin53.4)^2 然后判断其数值大小。
如果Sap>Sab Sbp=Sap-Sab
如果 Sap

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