(1)(x^2/x)-y-x-y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)
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(1)(x^2/x)-y-x-y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)(1)(x^2/x)-y-x-y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)(1
(1)(x^2/x)-y-x-y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)
(1)(x^2/x)-y-x-y
(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)
(1)(x^2/x)-y-x-y(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)
(1)x^2/x)-y-x-y
=x-y-x-y
=-2y
(2)(a/a-b)-(a/a+b)-(2b^2/a^2-b^2)
=a(a+b-a+b)/(a^2-b^2)-(2b^2/a^2-b^2)
=2b/(a+b)
第一题不是等于2y吧
^ 是什么意思?
(1) -2y
(1)(x^2/x)-y-x-y
=x-x-2y
+-2y
(2)(a/a-b)-(a/a+b)-(2b^2/a^-b^2)
=2b/(a+b)
楼主有时间上网提问不如好好练习
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