(x-y)(2x-y-1)
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(x-y)(2x-y-1)(x-y)(2x-y-1)(x-y)(2x-y-1)(1+5)×(10-6)=24(10-1-5)×6=24(a+b)2=22a2+b2+2ab=4a2+b2=4-2ab=4
(x-y)(2x-y-1)
(x-y)(2x-y-1)
(x-y)(2x-y-1)
(1+5)×(10-6)=24
(10-1-5)×6=24
(a+b)2=22
a2+b2+2ab=4
a2+b2=4-2ab=4+2=6
所以b/a+a/b
=(a2+b2)/ab
=6/(-1)
=-6
1/(2x) - 1/(x+y)*((x+y)/(2x)-x-y)
=1/(2x) - 1/(x+y)*(x+y)(1/2x-1)
=1/(2x) - (1/2x-1)
=1
1+2得到2x+z=27.........4
1+3得到3x+2z=44...........5
4*2得到4x+2z=54............6
6-5得到x=10
把x=10代入5得到2z=44-30
z=7
把x=10代入2得到10-y=1
y=9
所以原方程组的解为x=10,y=9,z=7
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