2x3+3x2-4x-1

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2x3+3x2-4x-12x3+3x2-4x-12x3+3x2-4x-12x^3+3x^2-4x-1=x^3-1+x^3+3x^2-4x=(x-1)(x^2+x+1)+x(x^2+3x-4)=(x-1

2x3+3x2-4x-1
2x3+3x2-4x-1

2x3+3x2-4x-1
2x^3+3x^2-4x-1
=x^3-1+x^3+3x^2-4x
=(x-1)(x^2+x+1)+x(x^2+3x-4)
=(x-1)(x^2+x+1)+x(x-1)(x+4)
=(x-1)[(x^2+x+1)+x(x+4)]
=(x-1)(x^2+x+1+x^2+4x)
=(x-1)(2x^2+5x+1)

2x3+3x2-4x-1 1.证明（8-7x-6x2+x3）+(x3+5x2+4x-1)-(-x2-3x+2x3-3)的值与x无关.快, 求证:无论X取何值下列（8-7X-6X2+X3)+(X3+5X2+4X-1)-(-X2-3X+2X3-3)结果不变因式分解（1+x+x2+x3)2-x3 化简求值2X3+4X-1/3X2-(X+3X2-2X3) 其中X=-3 化简求值2X3+4X-1/3X2-(X+3X2-2X3) 其中X=-3 已知x2+5x-4=0,求x3+6x2+x+2的值已知x2+x-1=0,求x3+2x2+3的值 2x3+4x- x2-(x+x2-2x3) ,其中x= -3 计算(x3+x2+x+2)/(x2+1) (2x4-5x2-4x+1)-(3x3-5x2-3x) X2+X+1=0 X4+2X3+4X2+3X+2=? 已知x2-3x+1=0,求x4-6x3+4x2+15x+2 线性代数的题,如图.已知两个基α1= x3+2x2-x β1=2x3+x2+1α2=x3-x2+x+1 β2=x2+2x+2α3=-x3+2x2+x+1 β3=-2x3+x2+x+2α4=-x3-x2+1 β4=x3+3x2+x+2求坐标变换公式解方程组 X1-X2-4X3=-1 X2+X3=2 X1+X2-2X3=3线性代数已知X=√2-1,求x3+3x2+4/x2+1的值分解因式：-27x3+8 ,(x2-5x+2)(x2-5x+4)-24 ,x5+x4+x3+x2+x1+1 3-X2+X-1分之X4+X3-2乘以x3+2x2+2x+2分之X四次方-1除以-2分之X3-X-X2+1化简 x3+x+2 x3-4x2-4x-5 因式分解