x+y+z=651 (1+10％）x=y (1+5％）y=z 解这个方程组x+y+z=651 (1+10％）x=y(1+5％）y=z是这样

已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? x+y+z=651 (1+10％）x=y (1+5％）y=z 解这个方程组x+y+z=651 (1+10％）x=y(1+5％）y=z是这样 (x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=? 已知实数X.Y.Z满足(Y+Z)分之X+(Z+X)分之Y+(X+Y)分之Z=1,则(Y+Z)分之X平方+(Z+X)分之Y平方+(X+Y)分之Z平方的值为（ ） (x+y-z)(x-y+z)= x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0）,求x+y+z分之x+y-z 分式加减法：已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z 已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z的步骤 已知x+y/z=x+z/y=y+z/x(x+y+z≠0）,求x+y-z/x+y+z的步骤 100x+10y+z=27(x+y+z) x+z=y+1 100z+10y+x-100x-10y-z=99 解方程组100x+10y+z=27(x+y+z) x+z=y+1 100z+10y+x-100x-10y-z=99 .急. 1.设有比例式：x/(y+z)=y/(x+z)=z/(x+y),有比例性质,得x/(y+z)=y/(x+z)=z/(x+y)=（x+y+z)/[(y+z)+(x+z)+(x+y)]=0.5x/(y+z)=y/(x+z)=(x-y）/[（y+z）-（x+z)]=-1,由此可得0.5=-1试分析推理产生错误的原因 已知x,y,z>0,xyz(x+y+z)=1,求证（x+y）(x+z)>=2 (x-y-z)*( )=x²-（y-z）² 解方程组：{x(x+y+z)=6 {y(x+y+z)=9 {z(x+y+z)=10 1)x+y-z=13 2）x+y=16 y+z-x=-1 y+z=12z+x-y=3 z+x=10 解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10y+z）=99 X+Y+Z=? （x+y+z）*（-x+y+z）*（x-y+z）*（x+y-z）=