若M/(X+3) - N/(X-3)=8X/(X²- 9)则M*N为多少?
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若M/(X+3)-N/(X-3)=8X/(X²-9)则M*N为多少?若M/(X+3)-N/(X-3)=8X/(X²-9)则M*N为多少?若M/(X+3)-N/(X-3)=8X/(X
若M/(X+3) - N/(X-3)=8X/(X²- 9)则M*N为多少?
若M/(X+3) - N/(X-3)=8X/(X²- 9)则M*N为多少?
若M/(X+3) - N/(X-3)=8X/(X²- 9)则M*N为多少?
原式化为
(MX-3M-NX-3N)/(X²- 9)=8X/(X²- 9)
则MX-3M-NX-3N=8X
(M-N)X-3(M+N)=8X
当M-N=8;M+N=0时,等式成立
M=4,N=-4
M*N=-16
同分 等式两边分母一致
X项前面系数提出
常数项提出
构建2元一次方程组
解一下就出来了
M/(X+3) - N/(X-3)=(mx-3m-nx-3n)/(x²-9)
∴m-n=8
-3m-3n=0,即m+n=0
解得m=4,n=-4
mn=-16
M/(X+3) - N/(X-3)=8X/(X²- 9)
[M(X-3)-N(X+3)]/[(X+3)(X-3)]=8X/(X²- 9)
(MX-3M-NX-3N)/(X²- 9)=8X/(X²- 9)
(M-N)X-3M-3N=8X
所以M-N=8
-3M-3N=0即M+N=0
解得M=4 N=-4
M*N=-4*4=-16
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