一道英语的微积分问题The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 4 cos πt,where t is measured in seconds.(Round your answers to two decimal p
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一道英语的微积分问题The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 4 cos πt,where t is measured in seconds.(Round your answers to two decimal p
一道英语的微积分问题
The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 4 cos πt,where t is measured in seconds.(Round your answers to two decimal places.)
(a) Find the average velocity during each time period.
(i) [1,2]
cm/s
(ii) [1,1.1]
cm/s
(iii) [1,1.01]
cm/s
(iv) [1,1.001]
cm/s
(b) Estimate the instantaneous velocity of the particle when t = 1.
cm/s
一道英语的微积分问题The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin πt + 4 cos πt,where t is measured in seconds.(Round your answers to two decimal p
求平均速度是么
s = 2sinπt+4cosπt
V(1-2)=(S2-S1)/(2-1)=(0+4)-(0-4)=8
同理V(1-1.1)=[2sin(1.1π)+4cos(1.1π)+4]/0.1≈4.22
V(1-1.01)=[2sin(1.01π)+4cos(1.01π)+4]/0.01≈6.08
V(1-1.001)=[2sin(1.001π)+4cos(1.001π)+4]/0.001≈6.26
s = 2sinπt+4cosπt
v=ds/dt=2πcosπt-4πsinπt
瞬时速度v1=2π*1-4π*0=2π
对嘛，题目在A问中让你求一段时间内的平均速率。直接算出位移displacement然后除以时间。通过A问过渡到B问t=1时的瞬时速度，直接求函数的导数然后代入t=1就行了。那你说说答案吧~， 我看到sin 和cos在里面就不会算了。。s ‘= 2πcos πt - 4πsin πt 带入t=1，得s'(1)=-2π...
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对嘛，题目在A问中让你求一段时间内的平均速率。直接算出位移displacement然后除以时间。通过A问过渡到B问t=1时的瞬时速度，直接求函数的导数然后代入t=1就行了。
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