sin(pi/12)=?

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sin(pi/12)=?sin(pi/12)=?sin(pi/12)=?cos(π/6)=1-2[sin(π/12)]^2所以sin(π/12)=√[(1-cos(π/6)/2]=√[(3-√3)/6

sin(pi/12)=?
sin(pi/12)=?

sin(pi/12)=?
cos(π/6)=1-2[sin(π/12)]^2
所以sin(π/12)=√[(1-cos(π/6)/2]=√[(3-√3)/6]

sin(pi/12)=sin (pi/3-pi/4)=sin pi/3cospi/4-cospi/3sinpi/4=根号6/4-根号2/4