求y=3-2cos(2x-π/3),x∈[π/6,π/2]的值域

已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 y =(cos^2) x - sin (3^x),求y' Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) y=cos^3(2x)+e^x求导数 sin(x+y)cosx+cos(x+y)sinx=1/3 x∈(3π/2,2π) 求cos(2x+π/4) 求值域y=3+cos(2x-π/3) 求函数y=cos(x-π/3),x∈[-π/2,π/2]的值域, 求值域y=2sinx+cos^2x,x∈[π/6,2π/3) 求y=-cos(2x-π/3)在x∈[0,π/2]的值域 求函数y=cos^2x+3cos x+2,x属于【0,π/2)的值域? 当cos^2x-cos^2y=√3/2时,求sin(x+y）×sin(x-y) 求y=sin（π/3-2x）+cos（π/3+2x）x∈R的最大值 求y=sin＾2(x)+3sin(x)cos(x)-2cos＾2(x)的最大值 求y=sin x +2sin x cos x -3cos²x 的周期和值域, 求下列函数导数y=cos（π/3-x）y=e^3xy=In(3-x)y=cos^3(1-2x) 求值域!y=-cos^2 x+sinx+3 y=cos(π/3-x)cos[π/2（x-1)]判断奇偶性y=cos(π/3-x)cos(π/3+x)判断奇偶性 求下列函数的导数:y=x-sin x/2 cos x/2 y=x^3+3^x