lim(3^(n+1)-2^n)/(3^n+2^(n-1))=
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lim(3^(n+1)-2^n)/(3^n+2^(n-1))=lim(3^(n+1)-2^n)/(3^n+2^(n-1))=lim(3^(n+1)-2^n)/(3^n+2^(n-1))=lim(3^(
lim(3^(n+1)-2^n)/(3^n+2^(n-1))=
lim(3^(n+1)-2^n)/(3^n+2^(n-1))=
lim(3^(n+1)-2^n)/(3^n+2^(n-1))=
lim(3^(n+1)-2^n)/(3^n+2^(n-1))
=(上下同时除以2^(n+1))lim(3/2-1/2)/[(3/2)^n*1/2+1/2]
=(由于分子为1,分母为无穷大)0
你这是几年级的问题?
上下同除以3^n,很容易得出答案3
楼上别再误人子弟了
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lim(3^(n+1)-2^n)/(3^n+2^(n-1))=