满足-1/2=

满足-1/2= 求满足1/2 若复数z满足|z+1-i|=2,则满足|z-2+i|的最大值 满足不等式2x-1 y=log2(2x-x^2)满足1 已知f(x)=ax^2+bx,满足1 满足cosa=1/2的角的集合 已知f(x)=ax^2+bx,满足1 满足-1 若x1满足2x+2^x=5,x2满足2x+2log2(x-1)=5 已知正数a,b满足ab=1,则满足不等式a/a^2+1+b/b^2+1 已知三角形ABC为等边三角形,AB=2,设点P,Q满足满足满足向量AP=入向量AB,向量AQ=(1-已知三角形ABC为等边三角形,AB=2,设点P,Q满足满足满足向量AP=入向量AB,向量AQ=（1-入）向量AC,λ∈R,若BQ.CP=-3/2,则λ= 实数xy满足y>=1 y 写出一个满足不等式2x-1 满足式子lg(2m-1) 若a满足(a2+a+1)^-2 为什么我的满足1!+2!+...+n! 已知数列An满足An＞0,其前n项和为Sn为满足2Sn=An的平方+An(1)求An(2)设数列Bn满足An/2的n次方,Tn=b1+b2+