已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=? y=?

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已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=?y=?已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=?y=?已知│2x-y-3│+(2x+y+11)

已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=? y=?
已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=? y=?

已知│2x-y-3│+(2x+y+11)×(2x+y+11)=0,则x=? y=?
根据已知可知:2X-Y-3=0
2X+Y+11=0
解方程得:X=-2,Y=-7

由上得2x-y-3=0,2x+y+11=0
解得x=-2,y=-7

2x-y-3=0
2x+y+11=0
x=-2,y=-7

2x-y-3=0
2x+y+11=0
x=2 y=-7

由绝对值和完全平方都大于等于零
所以
2x-y-3=0(1)
2x+y+11=0(2)
(1)+(2)4x+8=0
x=-2
y=-7

因为│2x-y-3│>=0,
(2x+y+11)×(2x+y+11)=(2x+y+11)^2>=0,
而两数相加的和是0,
因此只有可能│2x-y-3│=0,
(2x+y+11)^2=0,
得到2x-y-3=0,2x+y+11=0,得x=-2,y=-7。