已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值./:是分数线
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已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值./:是分数线已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值./:是分数线已知x(x-1)
已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值./:是分数线
已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值.
/:是分数线
已知x(x-1)-(x^2-y)=-2,求:(x^2+y^2/2)-2xy的值./:是分数线
已知等式可以化简成x^2-x-x^2+y=-2,即y=x-2
将上式代入待求式得:
待求式=x^2+(x-2)^2/2-2*x*(x-2)
=x^2(1+0.5-2)+x(-2+4)+2
=-0.5x^2+2x+2
这个式子是求最大值还是就可以了,不是太明白题意.
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