1/5X1/6+1/6X1/7+1/7X1/8+1/8X1/9+1/9X1/10简便方法如何解

数学题1/4x1/5x1/6+1/5x1/6x1/7+1/6x1/7x1/8+.+1/98×1/99×1/100=? 提问:1x1/2+1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7 用简便方法 简便计算题1x1/2+1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6+1/6x1/7 1/5X1/6+1/6X1/7+1/7X1/8+1/8X1/9+1/9X1/10简便方法如何解 1/5x1/6+1/6x1/7+1/7x1/8+1/8x1/9+1/9x1/10请问用简便方法如何解。 数学题1/4x1/5x1/6+1/5x1/6x1/7+1/6x1/7x1/8+.+1/98×1/99×1/100=? 谢谢!要过程 求tan[(x1+x2)/2]及tanx1 * tanx2设x1,x2为以x为变量方程5cosx+6sinx=7的两根,不解x1,x2,求1)tan[(x1+x2)/2]及tanx1 * tanx2 1.x^2-3x-18=0 2.x^2+3x-5=0 3.x^2-4x-7=0 4.3^2-6x-9=0 5.3x^2-6x-9=0不解方程求：x1+x2=...x1乘以x2=...1/x1+1/x2=...x1^2+x2^2=...（x1-x2）^2=. 1/2X1/3+1/3X1/4+1/4X1/5+1/5X1/61/2X1/3+1/3X1/4+1/4X1/5+1/5X1/6简单的计算起来 3x1/4十4x1/5十5X1/6十6X1/7十7X1/8十8X1/9十9x1/10= 人教版六年级数学基础训练第10页小探究第二题简便计算下面两题(1) 1X1/2＋1/2X1/3＋1/3X1/4＋1/4X1/5＋1/5X1/6＋1/6X1/7(2) （1/4X1/7＋1/7X1/10＋1/10X1/13＋1/13X1/16)X3现在就要! //用牛顿迭代法求方程2x^3-4*x^2+3*x-6=0的根,最后答案错误,//用牛顿迭代法求方程2x^3-4*x^2+3*x-6=0的根#include#includevoid main(){double x0,x1;x0=1.5;x1=x0;x0=6/(2*x1*x1-4*x1+3);if(fabs(x0-x1)>=1e-5){x1=x0;x0=6/(2*x1*x1-4*x1+3 已知x1和x2是方程x^2+6x+7的两根,求下列各式的值.1）（x1-x2)^2 2)x1/x2+x2/x1 设x1,x2是方程3x方-5x-7=0的两根.求（1）x1方+x2方=?（2）1/x1+1/x2=?(3)X2/X1+X1/X2=? 1X+1.5x1.6=10. matlab 错误,function z=Shubert(x1,x2) %Shubert函数figure(1);x1=-10:.1:10;x2=x1;x=[x1 x2][x1,x2]=meshgrid(x1,x2);z=((1*cos(2*x1+1))+(2*cos(3*x1+2))+(3*cos(4*x1+3))+(4*cos(5*x1+4))+(5*cos(6*x1+5)))*((1*cos(2*x2+1))+(2*cos(3*x2+2))+(3*cos(4*x2+3))+( 简便运算：1又6分之1X1又7分之1X1又8分之1X1又9分之1X1又10分之1 1又1/6x1又1/7x1又1/8x1又1/9x1又1/10= 不要直接给答案,要递等式