已知logx(a)=2 logx(b)=3 logx(c)=6 求logabc(x)

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已知logx(a)=2logx(b)=3logx(c)=6求logabc(x)已知logx(a)=2logx(b)=3logx(c)=6求logabc(x)已知logx(a)=2logx(b)=3lo

已知logx(a)=2 logx(b)=3 logx(c)=6 求logabc(x)
已知logx(a)=2 logx(b)=3 logx(c)=6 求logabc(x)

已知logx(a)=2 logx(b)=3 logx(c)=6 求logabc(x)
换底公式
lga/lgx=2
lgb/lgx=3
lgc/lgx=6
相加
(lga+lgb+lgc)/lgx=11
lg(abc)/lgx=11
lgx/lg(abc)=1/11
所以logabc(x)=1/11

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