【x＋2y】【5a＋3b-2c】=【】【过程】

几道 数学题急啊 对了再加20分(x+y)^2-(x+y)^3(x-y)^2-(x-y)^3 (x-y)^2-(y-x)^32(x-y)-3(y-x)^24ab(a+b)^2-6a^2b(a+b)(x+y)(x-y)-(x+y)^28a(x-y)^2-4b(y-x)a=-5 a+b+c=-5.2求代数式a^2(-b-c)-3.2a(c+b)的值 【x＋2y】【5a＋3b-2c】=【】【过程】 x+y-(2x-y)(x+y)=?12(a^2-b^2)^2-3(a^2+b^2)(a+b)^2等于多少(2a-b)(2a+3b)+3a(b-2a)=-(2a-b)( ),a(x-3)(5-x)+b(3-x)(x-5)=( )(x-3)(a+b)代数式15x^3y^3(x-y),6x^2y^2(y-x),-120x^3y^3（x-y）（x+y）的公因式是?a-b+k(b-a)=( )(k-1)a(b-c)+c-b=(b-c) 对于有理数a,b,定义a*b=3a+2b,则(x+y)*(x-y)*3x化简后得什么 A.0 B.5X C.21X+3y D.9x+6y 初一因式分解练习题,谁好心帮我解下表示平方1.2X~-3XY-X2.(X+Y)~(X+Y)(X-Y)(X+Y)(Y+Z)3.3X(a+2b)~-6XY(a+2b)4.a(x-y)-b(X-Y)-C(Y-X)5.(b-a)~-2a+2b6.(x-y)~-m(y-x)+y-x7.x(x-y)(a-b)-y(y-x)(b-a)8.已知a+b=13,ab=40,求 b+ab~的值 a/b = 1-x/y 求b/a(a)x/(y-x)(b)y/x-1(c)y/(x-y)(d)x/y + 1(e)y/(y-x)第2题(3y-1)(2y+k) = ay的平方+by-5求a+b等于多少 ⑴x（a-x）（a-y）-y（x-a）（y-a）=⑵2x（a+b+c）,3y（a+b+c）的公因式是⑶-2（x-y）-（y-x）^2=⑷2m（a-c）-5（a-c） 1、(x+y)-(x+y)^32、x(x-y)-y(y-x)3、(a-b)^2-4b+4a4、a^n+1+a^n+a^n-15、x(x+y)(x-y)-x(x+y)^26、已知a+c-7=0,求(a+b)^2-2a(b-c)-2b(b-c)+(c-b)^2的值7、x^2-8y^2(x^2-2y^2) 下列去括号正确的是：x-(5y-3y)=x-5y-3z C:2x+(-3y+7)=2x-3y-7 B；a-3(b-c+b)=a-3b-3c-3dD:5x-[2y-(x-z)]=5x-2y+x-z 已知A=3x^2-12,B=5x^2*y^3+10x*y^3,C=(x+1)(x+3)+1求其公因式已知A=3x*x-12,B=5x*x*y*y*y+10x*y*y*y,C=(x+1)(x+3)+1求其公因式,若无,说出理由 9平面向量 已知a=(1,5),b=(-4,3),c=(x,y) (1)若2a+b-c=o,求x,y(2)若丨c丨=1,且c⊥b,求x,y 已知多项式A=x^2+2y^2-z^2,B=-4x^2+3y^2+2x^2,且A+B+C=0,则C为A.5x^2-y^2-x^2 B.3x^2-5y^2-z^2 C.3X^2-Y^2-3X^2.D.3X-5Y+Z^2 如果A={（x,y）|x,y+2>0},B={（x,y）|2x+3y-6>0},C={（x,y）|x-4 1.a/(b+c)=b/(a+c)=c/(a+b)=k,求k值.2.x/(y+z)=a,y/(z+x)=b,z/(x+y)=c,a/(1+a)+b/(1+b)+c/(1+c)=3.1/(x-2)(x-5)=A/(x-2)+B/(x-5),求A=___,B=___ A=2x^5-3x^2 y^3+2y^5,B=2x^2+xy-3y^2,C=x^2-xy-7y^2,且A+D-[B-(C-A)]=0,求D 解方程组2x/a+3y/b-4z/c=1,4x/a+2y/b-3z/c=3,3x/a+4y/b-2z/c=5 已知A=5x^+2xy-4y^,B=-x^-4xy+y^,C=x^-xy+3y^其中xy满足|2x+1|+(y-4)^=0,就A-2B+C已知A=5x^+2xy-4y^,B=-x^-4xy+y^,C=x^-xy+3y^其中xy满足|2x+1|+（y-4)^=0,求A-2B+C-2B+C的值 已知a+b>c,b+c>a,a+c>b求证a^3+b^3+c^3-a(b-c)^2-b(c-a)^2-c(a-b)^2-4abcc,b+c>a,a+c>b 所以不妨设a=x+y b=y+z c=z+x 其中x,y,z>0 则a^3+b^3+c^3-a(b-c)^2-b(c-a)^2-c(a-b)^2-4abc(化简消元）＝-2(x^2y+xy^2+y^2z+yz^2+z^2x+zx^2+4xyz)c,b+c>a,a+c>b