y=(x-1)÷2x-1y=x∧2(x ≤0)y=-x∧2(x≤0)y=-x∧2+2x+1(x≥1）

先化简,再求值:y(x-y)-x(x+y)/x²-y²÷x²+y²/x+y,其中x=2,y=-1 1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²] 1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]= x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 [(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1 [(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=1 先化简,再求值 （1）[(x-y)的平方+（x+y)(x-y)]÷2x 其中X=2010,y=2009 （2)y(x+y)+(x+y)(x-y)-x的平方,先化简，再求值（1）[(x-y)的平方+（x+y)(x-y)]÷2x 其中X=2010,y=2009（2)y(x+y)+(x+y)(x-y)-x的平方,其中x=-2,y=二分 [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y x+2y=2x+y+1=7x-y 求：2x-y? 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 二元一次方程 ：2(x+y)-(x-y)=3 (x+y)-2(x-y)=1 (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 y=(2x)/x-1化简成用y表示x