27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
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27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg527^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg527^1/3-1/2^log2(6)[6是真
27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log₂6-2lg1/4+4lg5
=(3^3)^(1/3)-1/6-2lg2^(-2)+4lg5
=3-1/6-2*(-2)lg2+4lg5
=17/6+4(lg2+lg5)
=17/6+4lg10
=17/6+4
=41/6
a^(logab)=b
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已知方程X+X*log2 (6)+log2 (3)=0的两根为a,B求(1/4)^a * (1/4)^B的值韦达定理a+b=-log2(6)原式=(1/4)^(a+b)=(1/4)^[-log2(6)]=4^log2(6)=(2^2)^log2(6)=2^2log2(6)=2^log2(6)=36怎么从=2^log2(6)得出36的
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