log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
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log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1
log2{(x+3)*(x+2)}=1
(x+3)*(x+2)=2
x^2+5x+4=0
(x+4)(x+1)=0
所以x=-4或-1
因为x+3>0 x+2>0
所以x>-2
所以x=-1
log2 (x + 3) (x + 2) =1
(x + 3) (x + 2) = 2
相信后面的步骤难不住你了
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 6-log2 3
log2^6-log2^3
log2(4)/log2(3)
log2^(x^log2^x)=?
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
求解log2(3x)=log2(2x+1)
不等式log2(2x+3)>log2(x+1)的解集是
log2(x+1)+log2(x+8)=3的解集是?
不等式log2(2x-3)
log2为底x+3
log2(x^2-3)>0
log2(3),log2(3^x-1),log2(3^x+37/3)成等差数列,求x
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计算:log2(log2 32-log2 3/4+log2 6)