log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1

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log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x+2)=1log2(x+3)+log2(x

log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1

log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2 (x + 3) + log2(x + 2) = 1
log2{(x+3)*(x+2)}=1
(x+3)*(x+2)=2
x^2+5x+4=0
(x+4)(x+1)=0
所以x=-4或-1
因为x+3>0 x+2>0
所以x>-2
所以x=-1

log2 (x + 3) (x + 2) =1
(x + 3) (x + 2) = 2
相信后面的步骤难不住你了