求解log2(3x)=log2(2x+1)

求解log2(3x)=log2(2x+1) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 |[log2(x)]^2-3log2(x)+1| [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 求解log2 (3X+2)-log4 (X)=3 log2(x+1)>log2(3-x) log2 (x+1)+log2 x=log6 log2(4^x+4)=x+log2(2^x+1-3)log2(4^x+4)=x+log2[2^(x+1)-3] 解方程log2(2-x)=log2(x-1)+1 解2log2^(x-5)=log2^(x-1)+1 log2(x+1)+log2(x+8)=3的解集是? 不等式log2(2x+3)>log2(x+1)的解集是 log2^(x^log2^x)=? 解方程log2(x+14)-log2(x+6)=3-log2(x+2) log2(2^x-1)log2(2^(x+2)-4=3log2(2^x-1)log2(2^(x+2)-4）=3 log2(x)=-1 log2(2X-1) 解方程log2(4^x+1)=x+log2(2^(x+3)-6)