log2(x+1)>log2(3-x)
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log2(x+1)>log2(3-x)log2(x+1)>log2(3-x)log2(x+1)>log2(3-x)且真数大于0所以x+1>3-x>0x+1>3-xx>13-x>0x所以1log2(x)
log2(x+1)>log2(3-x)
log2(x+1)>log2(3-x)
log2(x+1)>log2(3-x)
且真数大于0
所以x+1>3-x>0
x+1>3-x
x>1
3-x>0
x<3
所以1
log2(x)递增
且真数大于0
所以x+1>3-x>0
x+1>3-x
x>1
3-x>0
x<3
所以1
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
求解log2(3x)=log2(2x+1)
不等式log2(2x+3)>log2(x+1)的解集是
log2(x+1)+log2(x+8)=3的解集是?
log2 (x+1)+log2 x=log6
log2(3),log2(3^x-1),log2(3^x+37/3)成等差数列,求x
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
【x】表示不超过实数x的最大整数,则【log2 1]+[log2 2]+[log2 3]+.+[log2 2012]等于?
不等式log2 (x+1)
log2(2X-1)
log2(x²+1)
log2(x-1)
log2(x)=-1
log2(x+1)
log2(x-1)
log2(x-1)