log2(x-1)
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log2(x-1)log2(x-1)log2(x-1)因为底数都大于一log2(x-1)log2(x-1)2(x-1)2x-22xx要使对数函数有意义,真数x-1必须大于零,即:x>1①。又因为底数大
log2(x-1)
log2(x-1)
log2(x-1)
因为底数都大于一
log2(x-1)
log2(x-1)<2log2*3
2(x-1)< 6²
2x-2 < 36
2x < 38
x < 19
要使对数函数有意义,真数x-1必须大于零,即:x>1①。又因为底数大于1的对数函数是单调递增函数所以真数大者对数值就大。因此据题意,当log2^(x-1)<2log2^3=log2^3²=log2^9时,一定有:x-1<9,解之得:x<10②。 综合①②得:1<x<10。
|[log2(x)]^2-3log2(x)+1|
log2(x+1)>log2(3-x)
log2 (x+1)+log2 x=log6
不等式log2 (x+1)
log2(2X-1)
log2(x²+1)
log2(x-1)
log2(x)=-1
log2(x+1)
log2(x-1)
log2(x-1)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
.log2^(x+1/x+6)
log2(x-1)-log2(x+1)的定义域与值域
不等式|log2^x-1|不等式|(log2^x)-1|
解方程log2(2-x)=log2(x-1)+1
log2(x-1)>2定义域log2(x-1)>2 定义域
解2log2^(x-5)=log2^(x-1)+1