1 Find the equation of the straight line that passes through the points(3,-1)and (-2,2)mgiving your answer in the form ax+by+c=0.Hence find the coordinates of the points of intersection of the line and the x-axis.2 The point A has coordinates (2,_5).

来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/16 20:56:15
1Findtheequationofthestraightlinethatpassesthroughthepoints(3,-1)and(-2,2)mgivingyouranswerintheform

1 Find the equation of the straight line that passes through the points(3,-1)and (-2,2)mgiving your answer in the form ax+by+c=0.Hence find the coordinates of the points of intersection of the line and the x-axis.2 The point A has coordinates (2,_5).
1 Find the equation of the straight line that passes through the points(3,-1)and (-2,2)mgiving your answer in the form ax+by+c=0.
Hence find the coordinates of the points of intersection of the line and the x-axis.
2 The point A has coordinates (2,_5).The straight line 3x+4y-36=0 cuts the x-axis at B and the y-axis at C.Find
(a) the equation of the line through A which is perpendicular to the line BC;
(b) the perpendicular distance form A to the line BC
(c) the area of triangle ABC
为第2题目的另外2个题目。

1 Find the equation of the straight line that passes through the points(3,-1)and (-2,2)mgiving your answer in the form ax+by+c=0.Hence find the coordinates of the points of intersection of the line and the x-axis.2 The point A has coordinates (2,_5).
1〉 3x+5y-4=0 4/3
2〉 4x-3y-23=0

1
∵ax+by+c=0
∴
3a-b+c=0
{ -2a+b+c=0
so,5a=2b,a=-2c ,b=-5c
A:y=-2x/5+1/5
2

很简单的啊 我帮你翻译哦
1找到通过点（3、-1） （-2、2）的直线方程，答案用ax+by+c=0表达
2 点A的坐标为 (2,_5). 直线3x+4y-36=0和X轴交于B点 和Y轴交于C点
找到通过A点并垂直于BC的直线方程
很简单的高中数学啊

Find the equation of the line OP /> find the equation of the tangent at (0,2) to the circle with equation(x+2)平方 + (y+1)平方=13 这么做这数学(find the equation of the tangent) find the equation of the normal at the point (1,2)to the graph y=x+1/x Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1) Aand B are the roots of the equation x2-4x+6=0(i) Find the value of 1 1--- + ---A B 1 1(ii) Find the quadratic equation whose roots are -- and --A B Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? Find the equation of the perpendicular bisector of A(-2,1)and B(4,-5)perpendicular垂直bisector 等分 求翻译:Find the equation of the tangent and the normal respectively to the curve y=cos x at the point (Π/3,1/2) 原题是英文In questions 12-13,line t is tangent to the circle C1,of equation x2+y2-8x+10y+28=0 at (1,-3).t is also tangent to the circle C2 whose center is (3,-3).12.Find an equation of t.13.Find the standatd equation of C2.翻译：在12,13题 Find the equation of the locus of the mid-point of the chord ofthe curve x²+4y²=1 with gradient 1. Find an equation of the tangent line to the graph of the function f(x) = 8/(√x^2+3x) at the point (1,4) 1,P is the point (7,5) and L1 is the line with equation 3x+4y=16(1),Find out the equation of the line L2 which passes through P and is perpendicular to L2.(2),Find the point of intersection of the L1 and L2.(3),Find the perpendicular distance of P fr Alevel数学题?1.P is the point (7.5) and L1 is the line with equation 3x+4y=16(1).Find out the equation of the line L2 which passes through P and is perpendicular to L2.(2).Find the point of intersection of the L1 and L2.(3).Find the perpendicular 微积分.A curve is such that dy/dx = 16/x^3,and (1,4)is a point on the curve.(i) Find the equation of the curve.(ii)A line with gradient -1/2 is a normal to the curve.Find the equation of this curve,giving your answer in the form ax+by=c(iii)Find t 100分求一道数学题,Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). the line through the points(0,1/2,1) and (2,1,3) find parametric equation. 我的问题是,r0应该是啥? Find the equation of the tangent line at x=2 for f(x)=√(（4x+1)/(5x-1))100分题,