Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1)
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Findtheequationofthetangenttothecurvey=(x^2-5)^3atthepoint(2,-1)Findtheequationofthetangenttothecurv
Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1)
Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1)
Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1)
求导y'=6x(x²-5)²,
f'(2)=12,
所以y=12(x-2)-1=12x-25
找曲线y=(x^2-5)^3 在点(2-1)切线 不会就退学吧
y=(x^2-5)^3 在点(2-1)切线 求导数,设T=X^2-5 则 y = t^3 y'=3t^2*3t 带入x,和 t 就可以得到答案
Find the equation of the line OP />
这么做这数学(find the equation of the tangent)
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Find the equation of the tangent to the curve y=(x^2-5)^3 at the point (2,-1)
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