4条数列题

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4条数列题4条数列题 4条数列题1、既然an和bn都是等差数列,那么an+bn也是等差数列即a1+b1、a3+b3、a5+b5是等差数列,故a5+b5=2×21-7=352、Sn-1=(n-

4条数列题
4条数列题
 

4条数列题
1、既然an和bn都是等差数列,那么an+bn也是等差数列
即a1+b1、a3+b3、a5+b5是等差数列,故a5+b5=2×21-7=35
2、Sn-1=(n-1)²-9(n-1)=n²-11n+10,an=Sn-Sn-1=2n-10
3、S11=11a6,a6=2π/3,cos2π/3=-√3/2
4、a3=a1+2d,a4=a1+3d,(a1+2d)²=a1×(a1+3d),推出公比是1/2

1题an+bn也是等差数列,因此(a1+b1)+(a5+b5)=2(a3+b3)=>a5+b5=35
2题Sn-Sn-1=an=2n+8
3题an=(s2n-1)/(2n-1),a6=S11/11=2pi/3,cos2pi/3=1/2
4题a1*(a1+3d)=(a1+2d)^2,a1=-4d,a1=-4d,a3=-2d,a4=-d,所以公比为1/2