解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/24 11:06:41
解下列三元一次方程组:10x+20y+30z=4112x+20y+28z=4214x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54解下列三元

解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54
解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=54
10x+20y+30z=41
12x+20y+28z=42
14x+25y+40z=54

解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54
稍等

不知道对不对,有点乱
算的挺累的
对不,写的有点乱