int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func() {int z; z=x;x=y;y=z;x=2*x;y=2+y;}的运算结果是
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intx=10,y=20;main(){func();printf("%d,%d\n",x,y);}func(){intz;z=x;x=y;y=z;x=2*x;y=2+y;}的运算结果是intx=10
int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func() {int z; z=x;x=y;y=z;x=2*x;y=2+y;}的运算结果是
int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func() {int z; z=x;x=y;y=z;x=2*x;y=2+y;}
的运算结果是
int x=10,y=20; main() {func();printf("%d,%d\n",x,y);} func() {int z; z=x;x=y;y=z;x=2*x;y=2+y;}的运算结果是
x=40
y=12
前面的三条语句是完成了x,y 的互换
后面就不用说了
40 12
40 12
下列程序运行结果为() main() { int x=20,y; y=2
int x=10,y=20; main() {func();printf(%d,%d
,x,y);} func() {int z; z=x;x=y;y=z;x=2*x;y=2+y;}的运算结果是
#include int main(){ int x=0,y=0; while(x
#include void main() { int a=3,b=2,c=1; int x=10,y=20; if(a
main(){ int x=5; while(x
main() { int x=10; int y=x++; printf(%d,%d
,(x++,y),y++); }请先说出你的答案!
#include #include int main() { int x,y,sqrt; scanf (%d,&x); y=sqrt(x); if (x>
int x=10,y=20; main() { int k,y=5; k=f1(); printf(k=%d,x=%d,y=%d,k,x,y); k=f2();
public class Simple{public static void main(String args[]){simple(10);simple(int x){int y=x*x;System.out.println(y)}}}请帮我改正一下
main( ) { int x=010,y=10,z=0x10; printf(“%d,%d,%d
”,x,y,z); }
main( ) { int x=010,y=10,z=0x10; printf(“%d,%d,%d
”,x,y,z); }
#include using namespace std; int main() { int a,b,c; a=3; int f(int x,int y,int z);#include using namespace std; int main() {int a,b,c;a=3;int f(int x,int y,int z); cin>>a>>b>>c;c=f(a,b,c);cout
# include void p(int *x,int y){ ++*x; y=y+2; } void main() { int x=2,y=3; p(&y,y); printf(# includevoid p(int *x,int y){++*x;y=y+2;}void main(){int x=2,y=3;p(&y,y);printf(%d#%d,x,y);}
main() { int x=2002,y=2003; printf(%d
,(x,y)); } 为什么结果是2003?
main() { int x=2002,y=2003; printf(%d
,(x,y)); }
求高手解释一下这段程序#include class Test {int x,y; public: Test(int i,int j=0) {x=i;y=j;} int get(int i,int j) {return i+j;} }; void main() {Test t1(2),t2(4,6); int (Test::*p)(int,int=10); p=Test::get; cout
struct st{int x,int*y;}*p; int s[]={5,6,7,8} st a[]={10,&s[0],20,&s[1]30,&[2],40,&s[3]} main( ) {p=a;cout
main(){int a[]={2,4,6,8,10};int y=1,x,*p;p=&a[1];for(x=0;x