limx→-1.x^2-1/x^3-1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 18:28:29
limx→-1.x^2-1/x^3-1limx→-1.x^2-1/x^3-1limx→-1.x^2-1/x^3-1如果分母是x^3-1,直接代入x=-1,极限=0猜测分母是x^3+1因式分解limx→
limx→-1.x^2-1/x^3-1
limx→-1.x^2-1/x^3-1
limx→-1.x^2-1/x^3-1
如果分母是x^3-1,直接代入x=-1,极限=0
猜测分母是x^3+1
因式分解
limx→-1.x^2-1/x^3+1
=limx→-1 (x-1)(x+1)/(x+1)(x^2-x+1)
=limx→-1 (x-1)/(x^2-x+1)
=-2/3
lim (x^2-1/x^3-1)=lim2x/3x (罗比达法则)
=2/3
查百度
=limX(x→-1)(X-1)(X+1)/(X-1)(X^2+X+1)
=limX(x→-1)X+1/X^2+X+1
=0
1.limx→∞(1-1/2x)^x 2.limx→∞(1﹢x/x)^2x 3.limx→∞(1+1/x+3)^x 4.limx→0(1+2x)^1/x
limx→-1.x^2-1/x^3-1
limx→-1(x^3/x+1)
limx→∞(1+1/2x)^3x+2
limx→3 e^1/(x-3)(x-2)
limx→∞(2^x-1)/3^x=?
limx→∞ (1+2/x)^(x+3)求极限
limx→∞ (2x^3-x+1)
limx→1 x^2-x+1/x-1= limx→0+x^sinx=
求3个极限:limx→0 sin3x/2x=?limx→∞ xsin(1/x)=?limx→0 [sin(1/x)]/(1/x)=?
limx→-3 1/x-3=
limx趋于1 2/3x^3
微积分设f(0)=1.g(1)=2,f'(0)=-1,g'(1)=-2求:1、limx→0[cosx-f(x)]/x;2、limx→0[2^x*f(x)]/x;3、limx→1[根号x*g(x)-2]/x-1第二题更正2、limx→0[2^x*f(x)-1]/x
求极限 limx→∞ (x+1)(x+2)(x+3)(x+4)/x^4
求极限1.limx→-1(x^3+1)/sin(x+1); 2.limx→0(e^x-e^-x)/(sinx); 3.limx→+∞(ln(1+1/x))/(arccotx);4.limx→∞(tanx-sinx)/(1-cos2x);
limx→1(x^2-x+1)/(x-1)
limx→∞{x-x^2*In(1+ x^-1)
limx→0(2+x/2-x)∧1/x