x^2-y^2+4y-4x=x-y-kx+ky=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/10 14:11:51
x^2-y^2+4y-4x=x-y-kx+ky=x^2-y^2+4y-4x=x-y-kx+ky=x^2-y^2+4y-4x=x-y-kx+ky=x^2-y^2+4y-4x=(x+y)(x-y)-4(x

x^2-y^2+4y-4x=x-y-kx+ky=
x^2-y^2+4y-4x=
x-y-kx+ky=

x^2-y^2+4y-4x=x-y-kx+ky=
x^2-y^2+4y-4x
=(x+y)(x-y)-4(x-y)
=(x-y)(x+y-4)
x-y-kx+ky
=(x-y)-k(x-y)
=(x-y)(1-k)