设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3

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设函数y=f(x)=sinx^2+(2a-1)sinx+a^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin^2x+(2a-1)sinx+a^2+1/4，已知xЕ[5π/6

设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3
设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3
设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3

设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3
y=（sinx+a-1/2）^2+a
故要取放f（x）max,即a=1,sinx=1/2,即x=5π/6时
f(x)=2
当a=1/3,sinx=1/6时取得最小值放f（X）=1/3

设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+∮)(-兀 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f（x,y)=sin(x+y),那么f(0,xy）=( ) 设f(x)为可导函数,y=sin{f[sinf(x)]} dy/dx= 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2