设函数f(x)=sin(2x+∮)(-兀
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设函数f(x)=sin(2x+∮)(-兀设函数f(x)=sin(2x+∮)(-兀设函数f(x)=sin(2x+∮)(-兀(1)2x+∮=π/2+kπ,将x=π/8带入,可以解得∮=-3π/4(2)单调
设函数f(x)=sin(2x+∮)(-兀
设函数f(x)=sin(2x+∮)(-兀
设函数f(x)=sin(2x+∮)(-兀
(1)2x+∮=π/2+kπ,将x=π/8带入,可以解得∮=-3π/4
(2)单调递增区间-π/2+2kπ
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