siny=1/3,sin(x＋y)=1,求sin(2x＋y)
来源：学生作业帮助网 编辑：六六作业网 时间：2025/01/22 12:39:55
siny=1/3,sin(x＋y)=1,求sin(2x＋y)siny=1/3,sin(x＋y)=1,求sin(2x＋y)siny=1/3,sin(x＋y)=1,求sin(2x＋y)sin(x＋y)=1
siny=1/3,sin(x＋y)=1,求sin(2x＋y)
siny=1/3,sin(x＋y)=1,求sin(2x＋y)
siny=1/3,sin(x＋y)=1,求sin(2x＋y)
sin(x＋y)=1 所以可得：cos(x+y)=0
sin(2x+2y)=2sin(x+y)cos(x+y)=0
cos(2x+2y)=cos^2(x+y)-sin^2(x+y)=-1
siny=1/3 所以可得：cosy=±√[1-sin^2y]=±2√2/3
当：cosy=2√2/3 时有：
sin(2x+y)
=sin(2x+2y-y)
=sin(2x+2y)cosy-cos(2x+2y)siny
=-2√2/3
当cosy=-2√2/3 时有：
sin(2x+y)
=sin(2x+2y-y)
=sin(2x+2y)cosy-cos(2x+2y)siny
=2√2/3
siny=1/3,sin(x＋y)=1,求sin(2x＋y)
cosx-cosy=1/2,sinx-siny=1/3,sin(x+y)=RT
sinx+cosy=1/3 cosx+siny=1/6 则sin(x+y)=?RT
sinx-siny=1/3,cosx-cosy=2/3,sin(x+y)=?
sinx+cosy=1/3 cosx+siny=1/6 则 sin(x+y)?
sinx+siny=-1/3 cosx+cosy=1/2,求sin(x+y)的值.
证明sin(x+y)sin(x-y)=sinx-siny
已知x-y=派/3,且sin x-siny=1/2,求cos(x+y).
已知sinx+siny=1/3,cosx-cosy=1/5,求cos(x+y),sin(x-y).求过程!
证明sinx+cos(x+y)siny/cosx-sin(x+y)siny=tan(x+y)
请教微分方程：y'=1/(x+siny)
sin（x-y）cosy+cos（x-y）siny>=1,则x,y的范围分别是
sinx+siny=1/2,cosx+cosy=（根号3）/3,求sin[(x-y)/2]
已知sinx-siny=1/2,cosx-cosy=1/2,x、y均为锐角,求sin(x-y)
若sinx*siny=1 则sin(x+y)=?伤不起!有木有!cos（x+y）=？
已知：3sinY=sin(2X+Y),求证tan(X+Y)=2tanX
已知5siny=sin(2x+y),求证:tan(x+y)=3/2tanx
为什么sinx*cosy-cosx*siny=sin(x-y)