lingo出错,0.5*n*R^2*@sin(2*3.14159/n)=0.1; m=2/（R*（2*R+n））;k=8.89*2.71828^(-0.1714*n)+3.732*2.71828^(-0.005667*n);@gin(n);p=0.5;max=(p*1/k+(1-p)/4*0.1*m);

lingo出错,0.5*n*R^2*@sin(2*3.14159/n)=0.1; m=2/（R*（2*R+n））;k=8.89*2.71828^(-0.1714*n)+3.732*2.71828^(-0.005667*n);@gin(n);p=0.5;max=(p*1/k+(1-p)/4*0.1*m); matlab函数调用出错,R=30;m=0:R-1;K=1;s=cos(0.075*pi*m);u=rand(1,R)-0.5;x1=s+u;for n=1:500s=cos(0.075*pi*m);K=K+1;y{n}=ensemble_ave(s,R,K);e=MSE(s,y{n});end;subplot(231),plot(s);subplot(232),plot(u);subplot(233),plot(x1);subplot(234),plot(e);subp matlab程序老出错n=6; m=2;y=[601938035,723070269,1031882511,1160017381,1295330000,1370536875];x=[1953,1964,1982,1990,2000,2010];X=[ones(n,1),x'];[b,bint,r,rint,s]=regress(y',X);s2=sum(r.^2)/(n-m-1);b,bint,s,s2rcoplot(r,rint) 求助!这是我第一次接触LINGO,因为写论文要建模,我输入了一下这段,可是跳错,求大侠帮忙看看 哪里出错MODEL:SETS:S/S1..S4/: SI;D/D1..D4/: DJ, R, Y;LINKS (S,D): C,A,U,X;ENDSETSDATA:SI=10, 50, 200, 100;DJ=10, 100, 200, 5 s= 1/1!+1/2!+1/3!+1/4!+1/5!+.+1/n!程序哪里出错了?#include#includevoid main(){int m,n,r;long double q;double s=0.0;int p=1;scanf(%d,&n);for(m=1;m lingo程序出错,model:sets:定义行列号;lines/1..31/:line;rows/1..30/:row;网点编号;shop/1..11/:l,r,m,price;人口分布;popu(lines,rows):popudata;distribution(lines,rows,shop):p;endsets目标函数;max=@sum(distribution(I,J,S) | I#ge#1#and#J 求解以下简单Lingo程序,为啥出错model:title:complex linear program;sets:condit/1/:a,b;area/1..5/:p,u,r,q;row/1..2/:;link(area,row):x,t;end setsdata:p=0,0.01,0.02,0.045,0.065;q=0,0.025,0.015,0.055,0.026;r=0.05,0.28,0.21,0.23,0.25;u=0,103,198 P R N D - S + 算法分析与设计 证明如下定理如果f(n)=O(s(n))并且g(n)=O(r(n)),则f(n)+g(n)=O(s(n)+r(n))1、试证明下面的定理：(1) 如果f(n)=O(s(n))并且g(n)=O(r(n)),则f(n)+g(n)=O(s(n)+r(n))(2) 如果f(n)=O(s(n))并且g(n)=O(r(n)),则f(n)*g( 2用Lingo软件求解：max z= c^T*x+0.5*x^T*Q*x; s.t.-1 斐波那契数列通向公式的问题设常数r,s.使得F(n)-r*F(n-1)=s*[F(n-1)-r*F(n-2)].则r+s=1,-rs=1.n≥3时,有.F(n)-r*F(n-1)=s*[F(n-1)-r*F(n-2)].F(n-1)-r*F(n-2)=s*[F(n-2)-r*F(n-3)].F(n-2)-r*F(n-3)=s*[F(n-3)-r*F(n-4)].……F⑶-r*F⑵=s*[F D B Q R N S S S=nπR^2÷360 lingo查错model:sets:kinds/1..10/:v,Q,s,N,c_p,d,p;fa/1..3/;link(fa,kinds):c_d;endsetsmin=@sum(link(j,i):0.5*c_p*(Q-s)^2/Q+d*c_d/Q+0.5*p*s^2/Q);@sum(link(j,i):c_d*Q) Lingo 提示出错@FOR(INTERSECTION(I)|I#LE#2:(OFFSET(I,I+1)=0));这句话Lingo提示Missing Right parenthesis但我觉得没有少括号,错在哪里呢 LINGO问题 要用LINGO建模我的目标方程是算Min= 2225.04 + 321753.6/(0.5+R) + 576*P我有几组数据 当R=2的时候,P=7.75；当R=3.4的时候,P=9；当R=5的时候,P=13；当R=6的时候,P=17；当R=7的时候,P=21；当R=8.4的时候,P=2 lingo程序：MIN=（-2*x+x^2）*@exp （-x^2-y^2-x*y）;为什么总是显示出错 计算机 算法设计题1、试证明下面的定理：(1) 如果f(n)=O(s(n))并且g(n)=O(r(n)),则f(n)+g(n)=O(s(n)+r(n)) (2) 如果f(n)=O(s(n))并且g(n)=O(r(n)),则f(n)*g(n)=O(s(n)*r(n))2Show that lgn!= θ(n lg n)(Not:that lgn!= θ(n lg n) means t