2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值

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2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值2x-y=2,求[（x2+y2)-(x-y)2-2y

2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值
2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值

2x-y=2,求[（x2+y2)-(x-y)2-2y(x-y)]/4y的值
（x2+y2)-(x-y)2-2y(x-y)]/4y=(x2+y2-x2-y2+2xy-2yx+2y2)/4y=y/2