$2 double后是不是$4?a couple of dollars和double各是什么意思

$2 double后是不是$4?a couple of dollars和double各是什么意思 牛顿迭代法求根,方程为ax^3+bx^2+cx+d=0的系数a,b,c,d为1 2 3 4求1附近的一个实根#include #include using namespace std; int main() { double newton(double a,double b,double c,double d,double x0); double a,b,c,d,x0; couta>>b>>c>>d; cou 递归二分发求方程解#include using namespace std;double f(double t){return t*t*t-3*t+4;}double b(double a,double b,int n){double t=(a+b)/2;if(n==1||f(t)==0){return t;}if(f(a)*f(t)>x>>y;cin>>c;double s=b(x,y,c);cout C语言,用三个函数分别求b^2-4ac大于等于小于0时,方程ax^2+bx+c的根,从主函数输入a,b,c值#include stdio.hdouble a,b,c,r,disc;double *p,*q;double m[2],n[2];double r1(double x,double y) {r=y/(2*x);return(r);}double r2(double x,do int b(double l,double r) { double a; aint b(double l,double r){double a;a=(l+r)/2;if(a*a-6>0) b(l,a);else if(a*a-6 #includeusing namespace std;#define PI 314159double area(double radius=0);double area(double a,double b);double area(double a,double b,double h);double area(double a,double b,double c,int);int main(){cout double x=2.5 ; int a=7 ;double y=4.7 x+a%3*(int)(x+y)%2/4 该表达式的值及类型是什么啊? 二分法的问题#include #include #include #define MIN 0.001double f (double a,double b){double c;c = (sin(a) - a*a/4) * (sin(b) - b*b/4);printf ( c is :%lf ,c);return c;}double erfen( double a ,double b){double n;n = a - b;printf ( n is :%lf 【c++】现有三个函数（1）double Add(double a) (2)double Add(double a,double b) (3)……如题,(3) int Add(double a,double b,double c=0)现在对Add函数进行调用,编译出现错误的是A.Add(3) B.Add(3.3,3.4) C.Add(2.3,3.1,3.2) D.Add(3 CO(NH2)2即尿素是不是有机物? co（nh2）2是不是有机物 有句C语言看不懂double f (double a, double b, double c,double d, double x) double *p,a; *p 28g混合气体N2和CO求.所含原子总数.是不是混合后只有2个原子? 求方程 a*x^2+b*x+c=0的根,用3个函数分别求当b^2-4*a*c大于0、等于0、小于0时的根并输出结果.从主函数输不知道哪里错了,对于返回值那一点不是很清楚,#include#includemain(){double x(double x,double y,double C# double保留小数点后一位double a,b,c;c=a/b 想要c的值小数点后保留一位 不要四舍五入 c 程序 ：求方程ax2+bx+c=0的根,用三个函数分别求当b2-4ac大于0、等于0和小于0时的根,并输出结果.我已经写完差不多的程序了 如下：#include#includevoid deltaZero(double a,double b,double c){double ans=-b/(2*a);p c语言 编程 求方程ax2+bx+c=0的根,用三个函数分别求当b2-4ac大于0、等于0和小于0时的根,并输出结果.#include#includevoid deltaZero(double a,double b,double c){ double ans=-b/(2*a); printf(x1=x2=%lf ,ans);}void delt