t^4-4t^3+2t^2+1=0怎么分解
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t^4-4t^3+2t^2+1=0怎么分解t^4-4t^3+2t^2+1=0怎么分解t^4-4t^3+2t^2+1=0怎么分解原式可分解为t^4-t^3-3t^3+2t^2+1=t^3(t-1)-(3
t^4-4t^3+2t^2+1=0怎么分解
t^4-4t^3+2t^2+1=0
怎么分解
t^4-4t^3+2t^2+1=0怎么分解
原式可分解为
t^4-t^3-3t^3+2t^2+1
=t^3(t-1)-(3t^3-2t^2-1)
=t^3(t-1)-(t-1)(3t+1)
=(t^3-3t-1)(t-1)
所以t=1
记得采纳哟亲
t^4-t^3 -3t^3+3t^2 -t^2+1=0
t^3(t-1) -3t^2(t-1)-(t+1)(t-1)=0
(t-1) (t^3-3t^2-t-1)=0
∴t=1
t^4-4t^3+2t^2+1
=t^4-3t^3-3t^3+3t^2-t^2+t-t+1
=(t-1)(t^3-3t^2-t-1)
=0
故t=1
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