1,2,2,4,( ),32.A.4 B.6 C.8 D.161,2,2,4,( ),32.A.4\x05B.6\x05C.8\x05D.16
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1,2,2,4,( ),32.A.4B.6C.8D.161,2,2,4,( ),32.A.4\x05B.6\x05C.8\x05D.161,2,2,4,( ),32.A.4B.6C.8D.161
1,2,2,4,( ),32.A.4 B.6 C.8 D.161,2,2,4,( ),32.A.4\x05B.6\x05C.8\x05D.16
1,2,2,4,( ),32.A.4 B.6 C.8 D.16
1,2,2,4,( ),32.
A.4\x05B.6\x05C.8\x05D.16
1,2,2,4,( ),32.A.4 B.6 C.8 D.161,2,2,4,( ),32.A.4\x05B.6\x05C.8\x05D.16
C
an=a(n-1)*a(n-2)
等于前面两个数的积
像这样的问题自己多尝试下,下次才会的!
1*2=2
2*2=4
2*4=8
4*8=32
选C
C
解析:满足 前2个相乘等于后一个数
1*2=2
2*2=4
2*4=8
4*8=32
C
c 1x2=2 2x2=4 2x4=8 4x8=32
a(a-1)(a-2)(a-3)(a-4)因式分解
计算[(a-1)/a*a-4*a+4]-[(a+2)/(a*a-2*a*a)]-4/a
求和:1,a+a^2,a^3+a^4+a^5,a^6+a^7+a^8+a^9,···(a不等于0)
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a-a a=[ ] [4]a-a=a+a a=[ ]
a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=?
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a/a^2-4 a-1/a-2 a+2/a^2-4a+4
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1/2-a-(a+2/a²-2a-a-1/a²-4a+4)÷a-4/2a
[(a/a-2)-(a/a+2)]÷4a/2-a,其中a=-1/2
[a^2-4/(a-3)(a+2)+(a+2)/a-3]除以a+1/a-3
5a-【a+(5a-2a)-2(a-3a)-4a】
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[(4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3)]
(1-16a×a×a×a)÷(4a×a+1)÷(2a+1)²