1,2,2,4,(  ),32.A.4 B.6 C.8 D.161,2,2,4,(  ),32.A.4\x05B.6\x05C.8\x05D.16

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1,2,2,4,(  ),32.A.4B.6C.8D.161,2,2,4,(  ),32.A.4\x05B.6\x05C.8\x05D.161,2,2,4,(  ),32.A.4B.6C.8D.161

1,2,2,4,(  ),32.A.4 B.6 C.8 D.161,2,2,4,(  ),32.A.4\x05B.6\x05C.8\x05D.16
1,2,2,4,(  ),32.A.4 B.6 C.8 D.16
1,2,2,4,(  ),32.
A.4\x05B.6\x05C.8\x05D.16

1,2,2,4,(  ),32.A.4 B.6 C.8 D.161,2,2,4,(  ),32.A.4\x05B.6\x05C.8\x05D.16
C
an=a(n-1)*a(n-2)
等于前面两个数的积
像这样的问题自己多尝试下,下次才会的!

1*2=2
2*2=4
2*4=8
4*8=32
选C

C
解析:满足 前2个相乘等于后一个数
1*2=2
2*2=4
2*4=8
4*8=32

C

c 1x2=2 2x2=4 2x4=8 4x8=32