int i,a; i=(a=2*4,a+5),a+6;不理解,

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inti,a;i=(a=2*4,a+5),a+6;不理解,inti,a;i=(a=2*4,a+5),a+6;不理解,inti,a;i=(a=2*4,a+5),a+6;不理解,结果=表达式1,表达式2,

int i,a; i=(a=2*4,a+5),a+6;不理解,
int i,a; i=(a=2*4,a+5),a+6;不理解,

int i,a; i=(a=2*4,a+5),a+6;不理解,
结果=表达式1,表达式2,……,表达式n;
此为顺序表达式,按顺序求出表达式1、表达式2、……、表达式n的值,结果为表达式n的值.
则i=(a=2*4,a+5),a+6;可以换成
a=2*4;
i=a+5;
a+6;
结果i=13.

a=8,逗号等式取最右侧的值,所以i=14

#define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i int i,a; i=(a=2*4,a+5),a+6;不理解, int a[]={1,2,3,4,2,4,5,2}; int b=LB(a,4)+LB(a+3,#includeint LB(int *a,int n) {int i,s=1;for(i=0;i #define N 20 fun(int a[],int n,int m) { int i; for(i=m;i>=n;i--) a[i+1]=a[i]; return a[a+1]; } main#define N 20fun(int a[],int n,int m){ int i;for(i=m;i>=n;i--)a[i+1]=a[i];return a[a+1];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i int*a[3] for(int i=0;i>ba[i]=new int[b] } void fun(int *a,int n) { int i,j,k,t; for(i=0;i #include void fun(int a[],int n) { int i,t; for(i=0;i 下列程序的输出结果是#define N 20void fun (int a[ ],int n,int m){int i,j;for (i=m;i>n;i--)a[i+1]=a[i];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i int a[10]={1,2,3,4,5},i;for(i=1;i int a[10],i ;for(i = 1; i 求详细解释,错误在哪里int a[] = {1 , 2 , 3 , 4} ;for(int i = 0 ; i < a.length ; i++)a[i + 1] *= a ;int expr = a[3] ; m=(int)(s[i]-'a')是什么意思 #include int main(void) { static int a[4][4]; }#include int main(void) { static int a[4][4]; int *p[4],i,j; for(i = 0; i < 4; i++) p[i] = &a[i][0]; for(i = 0 ; i < 4; i++) { *(p[i] + i) = 1 ; *(p[i] + 4 - (i + 1)) = 1; } for(i = 0; i < 4; i++) { for( int a[3][3]={{1,2,3},{4,5},{6}}; int i, main() {int a[6],i; for(i=1;i3))%5; printf(%2d,a[i]);} } #include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i #include void fun(int a,int b) {int t; t=a;a=b;b=t; } main() {int c[6]={1,2,3,4,5,6},i;for(i=0;i void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i