(x^3+y^3)(x+y)变成(x+y)^2 *(x^2-xy+y^2)急求(x+y)(x^3+y^3)=(x+y)^2(x^2-xy+y^2)
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(x^3+y^3)(x+y)变成(x+y)^2*(x^2-xy+y^2)急求(x+y)(x^3+y^3)=(x+y)^2(x^2-xy+y^2)(x^3+y^3)(x+y)变成(x+y)^2*(x^2
(x^3+y^3)(x+y)变成(x+y)^2 *(x^2-xy+y^2)急求(x+y)(x^3+y^3)=(x+y)^2(x^2-xy+y^2)
(x^3+y^3)(x+y)变成(x+y)^2 *(x^2-xy+y^2)急求
(x+y)(x^3+y^3)
=(x+y)^2(x^2-xy+y^2)
(x^3+y^3)(x+y)变成(x+y)^2 *(x^2-xy+y^2)急求(x+y)(x^3+y^3)=(x+y)^2(x^2-xy+y^2)
(x+y)(x^3+y^3)
=(x+y)(x+y)(x^2-xy+y^2)
=(x+y)^2(x^2-xy+y^2)
(3x-y)(3y+x)-(x-y)(x+y)
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(x^3+y^3)(x+y)变成(x+y)^2 *(x^2-xy+y^2)急求(x+y)(x^3+y^3)=(x+y)^2(x^2-xy+y^2)
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x(x-1)-(x^2-y)=-3 x^2-x-x^2+y=-3 -x+y=-3 x-y=3 你能告诉我为什么这个-x+y=-3会变成x-y=3吗?
推倒公式:(x+y)(x*x-3x+y*y)=x*x*x+y*y*y怎么做.