若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/24 05:28:03
若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)若√x-4y=4,(3x+5y)^3=-
若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)
若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)
若√x-4y=4,(3x+5y)^3=-27,求(x+y)^2n的值(n为整数)
√x-4y=4
所以x-4y=4²=16 (1)
(3x+5y)^3=-27=(-3)^3
所以3x+5y=-3 (2)
(2)-(1)*3
17y=-51
y=-3,x=4
(x+y)^2n
=(4-3)^2n
=1^2n
=1
(5x+3y)(3y-5x)-(4x-y)(4y+x)=
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
(x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)=
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
若5x+3y=3x+4y=x+2y+6,则x+y=___
若x/y=4/3 则3x+2y/2x-5y=
若2x-3y=0,求5x+4y/3x-2y
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
3X=5Y (X+Y)*3X=(2Y+X)*4+2*2
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
若(-x+6):(x-y):(4x+y)=3:14:1,求x+y
比例线段若x+y/x-y=4/3,则x/y=x+y/x-y=4/3,则x/y=要快~~
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()