2x+5y=5 3x-5y=10
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2x+5y=53x-5y=102x+5y=53x-5y=102x+5y=53x-5y=10由式1加上式2得2x+3x=5+10得5x=15解得x=3将其代入式1,得2*3+5y=5得5y=-1解得y=
2x+5y=5 3x-5y=10
2x+5y=5 3x-5y=10
2x+5y=5 3x-5y=10
由式1加上式2
得 2x+3x=5+10
得 5x=15
解得 x=3
将其代入式1,得 2*3+5y=5
得 5y=-1
解得 y=-1/5
即 x=3 y=-1/5
2x+5y=5……(1)
3x-5y=10 ……(2)
(1)+(2)得:
5x=15
x=3
将x=3带入(1)得:
6+5y=5
y=-1/5
所以答案是:
x=3
y=-1/5
将2x+5y=5 定为 方程①
将3x-5y=10 定为方程②
①+②得 5X=15
X=3
将X=3代入①得 6+5y=5
y=-1/5
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