.come on```要理由i已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则( )A.OA>AB>OB B.OA>OB>OC C.AB>OB>OA D.AB>OA>OB老大,你看卜懂就系开点```
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.comeon```要理由i已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则()A.OA>AB>OBB.OA>OB>OCC.AB>OB>OAD.AB>OA>OB老大,你看卜懂
.come on```要理由i已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则( )A.OA>AB>OB B.OA>OB>OC C.AB>OB>OA D.AB>OA>OB老大,你看卜懂就系开点```
.come on```要理由i
已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则( )
A.OA>AB>OB B.OA>OB>OC C.AB>OB>OA D.AB>OA>OB
老大,你看卜懂就系开点```
.come on```要理由i已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则( )A.OA>AB>OB B.OA>OB>OC C.AB>OB>OA D.AB>OA>OB老大,你看卜懂就系开点```
A=-1,B=1.5,C=3.2
O=0
所以 OA=|-1-0|=1
AB=|-1-1.5|=2.5
OB=|0-1.5|=1.5
OC=|0-3.2|=3.2
所以选C
OA=1
OB=1.5
OC=3.2
AB=2.5
实际上这应该是考究绝对值的
选择:C
C
OA=1,OB=1.5,AB=2.5
.come on```要理由i已知O是数轴上的原点,数轴的点A,B,C分别表示数-1,1.5,3.2,则( )A.OA>AB>OB B.OA>OB>OC C.AB>OB>OA D.AB>OA>OB老大,你看卜懂就系开点```
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