SAT求助,一道SAT题,我忘记公式了..In the xy-coordinate plane above,line contains the points (0,0) and (1,2).If line m (not shown) contains the point (0,0) and is perpendicular to ,what is an equation of (A) y = -1/2x (B) y = -1/2x+1 (C) y =
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SAT求助,一道SAT题,我忘记公式了..In the xy-coordinate plane above,line contains the points (0,0) and (1,2).If line m (not shown) contains the point (0,0) and is perpendicular to ,what is an equation of (A) y = -1/2x (B) y = -1/2x+1 (C) y =
SAT求助,一道SAT题,我忘记公式了..
In the xy-coordinate plane above,line contains the points (0,0) and (1,2).If line m (not shown) contains the point (0,0) and is perpendicular to ,what is an equation of
(A) y = -1/2x
(B) y = -1/2x+1
(C) y = -x
(D) y = -x+2
(E) y = -2x
请给出具体的解题步骤,公式忘的差不多了我...
SAT求助,一道SAT题,我忘记公式了..In the xy-coordinate plane above,line contains the points (0,0) and (1,2).If line m (not shown) contains the point (0,0) and is perpendicular to ,what is an equation of (A) y = -1/2x (B) y = -1/2x+1 (C) y =
Answer:(A)
Here's why:
According to the graph,we know that the equation for line l is y=2x.By given that line m is perpendicular to line l,so the slope for line m is -1/2( the product of the slope of two perpendicualr lines is always -1).We also know that line m goes through the point(0,0),by plugging this point to slope-intercept form(y=kx+b),we could easy get the equation for line m,which is y=-1/2x
如果你要考SAT的话就应该能看懂吧 o(∩_∩)o