已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,

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已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,已知1/x+1/y=2,求(x+y+2xy+

已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,
已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,

已知1/x+1/y=2,求(x+y+2xy+2y)÷(2xy+y)的值谢谢了,
(x+y+2xy+2y)÷(2xy+y)=(x+y/2xy)+(2xy/2xy)+(2y/y) =x+y/2xy+3 已知1/x+1/y=2 ∴x+y/2xy=1/2(1/X+1/y)=1/2×2=1 则原式=1+3=4