int x=2,y; y=(x++)*5;运行后x＝_____ __ y=____ ___.

int x,y; x=13; y=5; {printf(%d,x%=(y/=2)); int x=-5,y;cout void fun(int x,int y) {x=x+y;y=x-y;x=x-y; printf(%d,%d,,x,y); } main() {int x=2,y=3; fun(x,y); privoid fun(int x,int y){x=x+y;y=x-y;x=x-y;printf(%d,%d,,x,y);}main(){int x=2,y=3;fun(x,y);printf(%d,%d ,x,y);} int max(int x,int y) { int z; if(x>y) z=x; else z=y; return(z); # include void p(int *x,int y){ ++*x; y=y+2; } void main() { int x=2,y=3; p(&y,y); printf(# includevoid p(int *x,int y){++*x;y=y+2;}void main(){int x=2,y=3;p(&y,y);printf(%d#%d,x,y);} int x=5,y=2,z=0 1.x和y均为double型变量,且x=6.2,y=3.8求(int)x+y/y 2.设int x=2,y;则逗号表达式y=x+5,x+y Point(int x=0,int y=0):x(x),y(y){ count++; }我不懂 int x,y,z; x=2; y=4; z=7; x=y-- int x=2,y=3;则++x>y--?x:y的值为2, C语言 答案为什么是8 4 #includevoid f(int y,int *x){y=y+*x;*x=*x+y;}main(){int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} #includevoid f(int y,int *x){ y=y+*x; *x=*x+y;} void main(){ int x=2,y=4;f(y,&x);printf(%d,%d ,x,y);} c语言int x=15,y=5 x%=(y%=2) void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y=4; f(y,&x); printf(%d %d ,x,y); } void f( int y,int *x){y=y+*x; *x=*x+y;}main( ){ int x=2,y=4;f(y,&x);printf(%d %d ,x,y);} 执行后输出的结果是 . int x=2,y; y=(x++)*5;运行后x＝_____ __ y=____ ___. int x=5; int y=2+(x+=x++,x+8,++x); printf(%d,y); 求程序的结果并解释. int x=5; int y=2+(x+=x++,x+8,++x); printf(%d,y); 结果是多少,为什么?请大侠们解释清楚点, int fun(int x) { int y; if(x>1) y=fun(x-1)+2; else y=2; return y; } main(){ int y; y=fun(3);} y=?