求证:-sinθ=cos(π/2+θ)-sinθ=cos(π/2+θ)

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求证:-sinθ=cos(π/2+θ)-sinθ=cos(π/2+θ)求证:-sinθ=cos(π/2+θ)-sinθ=cos(π/2+θ)求证:-sinθ=cos(π/2+θ)-sinθ=cos(π

求证:-sinθ=cos(π/2+θ)-sinθ=cos(π/2+θ)
求证:-sinθ=cos(π/2+θ)
-sinθ=cos(π/2+θ)

求证:-sinθ=cos(π/2+θ)-sinθ=cos(π/2+θ)
cos(π/2+θ)=cos(π/2)*cosθ-sin(π/2)*sinθ=-sinθ