等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/14 18:20:39
等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=等

等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=
等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=

等比数列{an}中,a2+a4=3,a1a5=2,则a10/a8=
等比则a1a5=a2a4=2
a2+a4=3
韦达定理
a2,a4是x²-3x+2=0的根
则a2=1,a4=2或a4=1,a2=2
则q²=a4/a2=2或1/2
所以a10/a8=q²=2或1/2