[(x-y)^2-(x+2y)(x-2y)]/y

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[(x-y)^2-(x+2y)(x-2y)]/y[(x-y)^2-(x+2y)(x-2y)]/y[(x-y)^2-(x+2y)(x-2y)]/y=[(x²-2xy+y²)-(x&#

[(x-y)^2-(x+2y)(x-2y)]/y
[(x-y)^2-(x+2y)(x-2y)]/y

[(x-y)^2-(x+2y)(x-2y)]/y
=[(x²-2xy+y²)-(x²-4y²)]/y
=(x²-2xy+y²-x²+4y²)/y
=(5y²-2xy)/ y
=5y-2x

[(x-y)^2-(x+2y)(x-2y)]/y
=[x平方-2xy+y平方-x平方+4y平方]/y
=[5y平方-2xy]/y
=5y-2x