(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B
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(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B(x+5)/[(x+1)(x-3)]=A/(
(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B
(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B
(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B
待定系数法.
(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3)
得到:(x+5)/[(x+1)(x-3)]=[(A-B)x+(-3A-B)]/[(x+1)(x-3)]
A-B=1
-3A-B=5
所以,A=-1 B=-2
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(x+5)/[(x+1)(x-3)]=A/(x+1)-B/(x-3),求A、B
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