sin(-19π/6)/(sec4π/3)+tan7π/4=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 23:33:26
sin(-19π/6)/(sec4π/3)+tan7π/4=sin(-19π/6)/(sec4π/3)+tan7π/4=sin(-19π/6)/(sec4π/3)+tan7π/4=原式=sin(-19

sin(-19π/6)/(sec4π/3)+tan7π/4=
sin(-19π/6)/(sec4π/3)+tan7π/4=

sin(-19π/6)/(sec4π/3)+tan7π/4=
原式=sin(-19π/6+4π)cos(π+π/3)+tan(π+3/4π)
=-sin(5π/6)cos(π/3)+tan(3π/4)
=-1/2×1/2-1
=-5/4